What is the answer to 1+3/(x-5)= 3/(x^2-9x+20) ?

The answer to 1+3/(x-5)= 3/(x^2-9x+20) is x=1

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1+3/(x-5)= 3/(x^2-9x+20)

1 + \frac{3}{x - 5} = \frac{3}{x ^{2} - 9 x + 20}

x = 1

Solution steps

1 + \frac{3}{x - 5} = \frac{3}{x ^{2} - 9 x + 20}

Multiply by LCM

(x - 5) (x - 4) + 3 (x - 4) = 3

Solve

(x - 5) (x - 4) + 3 (x - 4) = 3 : x = 5, x = 1

x = 5, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 5, x = 4

Since the equation is undefined for:

5

x = 1

y, x^{y} = y^{x}

2^{x} - 3 x - 1 = 0

8^{x} + 2^{x} = 130

7^{x} = 70

a^{x}

What is the answer to 1+3/(x-5)= 3/(x^2-9x+20) ?
The answer to 1+3/(x-5)= 3/(x^2-9x+20) is x=1
Solve for x: 1+3/(x-5)= 3/(x^2-9x+20)
The solution is x=1