What is the answer to 3^{2-x}=400 ?

The answer to 3^{2-x}=400 is x=-(2ln(20)-2ln(3))/(ln(3))

Solve for x: 3^{2-x}=400

The solution is x=-(2ln(20)-2ln(3))/(ln(3))

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3^{2 - x} = 400

x = - \frac{2 ln ( 20 ) - 2 ln ( 3 )}{ln ( 3 )}

Decimal

x = - 3.45366 \dots

Solution steps

3^{2 - x} = 400

Apply exponent rules

(2 - x) ln (3) = ln (400)

Solve

(2 - x) ln (3) = ln (400) : x = - \frac{2 ln ( 20 ) - 2 ln ( 3 )}{ln ( 3 )}

x = - \frac{2 ln ( 20 ) - 2 ln ( 3 )}{ln ( 3 )}

2^{x^{2} + 2 x} = 8

5^{x} = 83

1 6^{r} \cdot 6 4^{3 - 3 r} = 64

y, 2^{2 y + 1} = x

2^{3 x - 3} = 3 2^{2 x + 5}

What is the answer to 3^{2-x}=400 ?
The answer to 3^{2-x}=400 is x=-(2ln(20)-2ln(3))/(ln(3))
Solve for x: 3^{2-x}=400
The solution is x=-(2ln(20)-2ln(3))/(ln(3))