What is the answer to 4^{2x-1}=3^{2x+3} ?

The answer to 4^{2x-1}=3^{2x+3} is x=(ln(108))/(2(2ln(2)-ln(3)))

Solve for x: 4^{2x-1}=3^{2x+3}

The solution is x=(ln(108))/(2(2ln(2)-ln(3)))

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4^{2 x - 1} = 3^{2 x + 3}

x = \frac{ln ( 108 )}{2 ( 2 ln ( 2 ) - ln ( 3 ) )}

Decimal

x = 8.13768 \dots

Solution steps

4^{2 x - 1} = 3^{2 x + 3}

Apply exponent rules

(2 x - 1) ln (4) = (2 x + 3) ln (3)

Solve

(2 x - 1) ln (4) = (2 x + 3) ln (3) : x = \frac{ln ( 108 )}{2 ( 2 ln ( 2 ) - ln ( 3 ) )}

x = \frac{ln ( 108 )}{2 ( 2 ln ( 2 ) - ln ( 3 ) )}

x, x r - e^{x} = 0

8^{x} = \frac{1}{2}

1 6^{x} + 4^{x} - 6 = 0

9^{x} = \frac{1}{3}

4^{a} = 64

What is the answer to 4^{2x-1}=3^{2x+3} ?
The answer to 4^{2x-1}=3^{2x+3} is x=(ln(108))/(2(2ln(2)-ln(3)))
Solve for x: 4^{2x-1}=3^{2x+3}
The solution is x=(ln(108))/(2(2ln(2)-ln(3)))