What is the answer to 4^{x^2+1}=2^{5x+5} ?

The answer to 4^{x^2+1}=2^{5x+5} is x=3,x=-1/2

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4^{x^2+1}=2^{5x+5}

4^{x^{2} + 1} = 2^{5 x + 5}

x = 3, x = - \frac{1}{2}

Decimal

x = 3, x = - 0.5

Solution steps

4^{x^{2} + 1} = 2^{5 x + 5}

Apply exponent rules

2 (x^{2} + 1) = 5 x + 5

Solve

2 (x^{2} + 1) = 5 x + 5 : x = 3, x = - \frac{1}{2}

x = 3, x = - \frac{1}{2}

x^{3} = 1. 5^{x}

4^{x + 2} - 3 \times 2^{x + 3} = 160

e^{x^{2}} \cdot 2 x = 0

3 (5^{x - 1}) = 21

4 \cdot 1 0^{2 - x} = 15

What is the answer to 4^{x^2+1}=2^{5x+5} ?
The answer to 4^{x^2+1}=2^{5x+5} is x=3,x=-1/2
Solve for x: 4^{x^2+1}=2^{5x+5}
The solution is x=3,x=-1/2