What is the answer to 3^{2-x}=3^{x^2} ?

The answer to 3^{2-x}=3^{x^2} is x=1,x=-2

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3^{2-x}=3^{x^2}

3^{2 - x} = 3^{x^{2}}

x = 1, x = - 2

Solution steps

3^{2 - x} = 3^{x^{2}}

Apply exponent rules

2 - x = x^{2}

Solve

2 - x = x^{2} : x = 1, x = - 2

x = 1, x = - 2

8^{x + 1} + 2^{3 x - 1} = \frac{17}{16}

9^{2 x} - 3 \cdot 9^{x} + 2 = 0

6 4^{2 x} = 1 6^{x + 1}

x \times e^{x} = 0

lo g_{2} (4^{x + 4}) = - 2

What is the answer to 3^{2-x}=3^{x^2} ?
The answer to 3^{2-x}=3^{x^2} is x=1,x=-2
Solve for x: 3^{2-x}=3^{x^2}
The solution is x=1,x=-2