What is the answer to 5^{2x-1}=8^{x+1} ?

The answer to 5^{2x-1}=8^{x+1} is x=(ln(40))/(2ln(5)-3ln(2))

Solve for x: 5^{2x-1}=8^{x+1}

The solution is x=(ln(40))/(2ln(5)-3ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{2 x - 1} = 8^{x + 1}

x = \frac{ln ( 40 )}{2 ln ( 5 ) - 3 ln ( 2 )}

Decimal

x = 3.23746 \dots

Solution steps

5^{2 x - 1} = 8^{x + 1}

Apply exponent rules

(2 x - 1) ln (5) = (x + 1) ln (8)

Solve

(2 x - 1) ln (5) = (x + 1) ln (8) : x = \frac{ln ( 40 )}{2 ln ( 5 ) - 3 ln ( 2 )}

x = \frac{ln ( 40 )}{2 ln ( 5 ) - 3 ln ( 2 )}

2^{2 x} - 4 \cdot 2^{x} + 4 = 0

4194304 = 4^{n - 1}

2^{4 x} = 8

3^{x} - 2 \times 3^{x - 2} = 7

2^{x + 1} + 5 (2^{x}) = 28

What is the answer to 5^{2x-1}=8^{x+1} ?
The answer to 5^{2x-1}=8^{x+1} is x=(ln(40))/(2ln(5)-3ln(2))
Solve for x: 5^{2x-1}=8^{x+1}
The solution is x=(ln(40))/(2ln(5)-3ln(2))