What is the answer to 2^{x+1}+5(2^x)=28 ?

The answer to 2^{x+1}+5(2^x)=28 is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x+1}+5(2^x)=28

2^{x + 1} + 5 (2^{x}) = 28

x = 2

Solution steps

2^{x + 1} + 5 (2^{x}) = 28

Factor

2^{x + 1} + 5 \cdot 2^{x} : 7 \cdot 2^{x}

7 \cdot 2^{x} = 28

Divide both sides by

7

2^{x} = 4

Apply exponent rules

x = 2

2^{2 x - 3} = 128

2^{2 x - 7} = 16

2 = (1.07)^{x}

6^{2 x + 1} = 216

12 5^{3 x + 7} = 2 5^{5 x - 11}

What is the answer to 2^{x+1}+5(2^x)=28 ?
The answer to 2^{x+1}+5(2^x)=28 is x=2
Solve for x: 2^{x+1}+5(2^x)=28
The solution is x=2