What is the answer to 19^x=2 ?

The answer to 19^x=2 is x=(ln(2))/(ln(19))

The solution is x=(ln(2))/(ln(19))

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19^x=2

1 9^{x} = 2

x = \frac{ln ( 2 )}{ln ( 19 )}

Decimal

x = 0.23540 \dots

Solution steps

1 9^{x} = 2

Apply exponent rules

x ln (19) = ln (2)

Solve

x ln (19) = ln (2) : x = \frac{ln ( 2 )}{ln ( 19 )}

x = \frac{ln ( 2 )}{ln ( 19 )}

5 \cdot 2^{x + 1} = 15

3 \times 2^{x} - 2^{x} = 1

e^{x^{2}} + 2 = 4

y, e^{x} y = 1

0 = 5^{x}