What are the solutions to the equation 9x^4-5x^2-4=0 ?

The solutions to the equation 9x^4-5x^2-4=0 are x=1,x=-1,x= 2/3 i,x=-2/3 i

Find the zeros of 9x^4-5x^2-4=0

The zeros of 9x^4-5x^2-4=0 are x=1,x=-1,x= 2/3 i,x=-2/3 i

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9 x^{4} - 5 x^{2} - 4 = 0

x = 1, x = - 1, x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

9 x^{4} - 5 x^{2} - 4 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

9 u^{2} - 5 u - 4 = 0

Solve

9 u^{2} - 5 u - 4 = 0 : u = 1, u = - \frac{4}{9}

u = 1, u = - \frac{4}{9}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 1 : x = 1, x = - 1

Solve

x^{2} = - \frac{4}{9} : x = \frac{2}{3} i, x = - \frac{2}{3} i

The solutions are

x = 1, x = - 1, x = \frac{2}{3} i, x = - \frac{2}{3} i

3 x^{3} + 15 x^{2} - 12 x = 0

2 x^{3} + 5 x^{2} - 6 x - 9

x^{3} + 3 x^{2} + x + 1 = 0

a, a^{4} = \frac{4}{3} a^{2} b + \frac{4}{9} b^{2}

y, x^{4} y - 20 = 0

What are the solutions to the equation 9x^4-5x^2-4=0 ?
The solutions to the equation 9x^4-5x^2-4=0 are x=1,x=-1,x= 2/3 i,x=-2/3 i
Find the zeros of 9x^4-5x^2-4=0
The zeros of 9x^4-5x^2-4=0 are x=1,x=-1,x= 2/3 i,x=-2/3 i