What are the solutions to the equation -4x^3=32 ?

The solutions to the equation -4x^3=32 are x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i

Find the zeros of -4x^3=32

The zeros of -4x^3=32 are x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i

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- 4 x^{3} = 32

x = - 2, x = 1 - 3 i, x = 1 + 3 i

Solution steps

- 4 x^{3} = 32

Divide both sides by

- 4

x^{3} = - 8

For

x^{3} = f (a)

the solutions are

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

x = 3 - 8, x = 3 - 8 \frac{- 1 + 3 i}{2}, x = 3 - 8 \frac{- 1 - 3 i}{2}

3 - 8 = - 2

Simplify

3 - 8 \frac{- 1 + 3 i}{2} : 1 - 3 i

Simplify

3 - 8 \frac{- 1 - 3 i}{2} : 1 + 3 i

x = - 2, x = 1 - 3 i, x = 1 + 3 i

r^{5} - r^{4} - 4 r^{3} - 4 r^{2} - 5 r - 3 = 0

x^{4} - 12 x^{3} - 14 x^{2} + 292 x + 577 = 0

2 x^{4} + 3 = 0

x^{3} - x^{2} + 6 x - 6 = 0

s^{3} + 6 s^{2} + 8 s + 10 = 0

What are the solutions to the equation -4x^3=32 ?
The solutions to the equation -4x^3=32 are x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i
Find the zeros of -4x^3=32
The zeros of -4x^3=32 are x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i