What are the solutions to the equation (x^3-1)^3=0 ?

The solutions to the equation (x^3-1)^3=0 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

Find the zeros of (x^3-1)^3=0

The zeros of (x^3-1)^3=0 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

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(x^{3} - 1)^{3} = 0

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Solution steps

(x^{3} - 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x^{3} - 1 = 0 : x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

The solutions are

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

(3 x + 2) (x^{2} - 25) = 0

6 x^{5} - 30 x^{4} = 0

6 x^{3} - 29 x^{2} - 6 x + 5

4 x^{3} - 8 x^{2} + x + 3 = 0

x^{3} + 2 x^{2} - x - 2

What are the solutions to the equation (x^3-1)^3=0 ?
The solutions to the equation (x^3-1)^3=0 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i
Find the zeros of (x^3-1)^3=0
The zeros of (x^3-1)^3=0 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i