What are the solutions to the equation roots x^3+2x^2-x-2 ?

The solutions to the equation roots x^3+2x^2-x-2 are x=-2,x=-1,x=1

Find the zeros of roots x^3+2x^2-x-2

The zeros of roots x^3+2x^2-x-2 are x=-2,x=-1,x=1

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roots

x^{3} + 2 x^{2} - x - 2

x = - 2, x = - 1, x = 1

Solution steps

x^{3} + 2 x^{2} - x - 2

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 2 x^{2} - x - 2 = 0

Factor

x^{3} + 2 x^{2} - x - 2 : (x + 2) (x + 1) (x - 1)

(x + 2) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - 2, x = - 1, x = 1

0 = 4 x^{3} - 12 x^{2} - 36 x

(1 + x)^{10} = \frac{1000}{910}

3 (1 + g)^{4} = 3.7

a, a^{4} - t^{4} = 6 a^{2} t

3 x^{4} - 8 x^{2} = - 4

What are the solutions to the equation roots x^3+2x^2-x-2 ?
The solutions to the equation roots x^3+2x^2-x-2 are x=-2,x=-1,x=1
Find the zeros of roots x^3+2x^2-x-2
The zeros of roots x^3+2x^2-x-2 are x=-2,x=-1,x=1