What are the solutions to the equation 4t^3-12t^2-72t+25=25 ?

The solutions to the equation 4t^3-12t^2-72t+25=25 are t=0,t=-3,t=6

Find the zeros of 4t^3-12t^2-72t+25=25

The zeros of 4t^3-12t^2-72t+25=25 are t=0,t=-3,t=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 t^{3} - 12 t^{2} - 72 t + 25 = 25

t = 0, t = - 3, t = 6

Solution steps

4 t^{3} - 12 t^{2} - 72 t + 25 = 25

Move

25

to the right side

4 t^{3} - 12 t^{2} - 72 t = 0

Factor

4 t^{3} - 12 t^{2} - 72 t : 4 t (t + 3) (t - 6)

4 t (t + 3) (t - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or t + 3 = 0 or t - 6 = 0

Solve

t + 3 = 0 : t = - 3

Solve

t - 6 = 0 : t = 6

The solutions are

t = 0, t = - 3, t = 6

4 x^{3} - 5 x + 2 = 24

2 x^{3} - 6 x^{2} + 13 x - 14 = 0

x^{3} = - 1 - i

7 x^{6} + 35 x^{4} = 42 x^{5}

- 2 x (- x^{2} + 12) = 0

What are the solutions to the equation 4t^3-12t^2-72t+25=25 ?
The solutions to the equation 4t^3-12t^2-72t+25=25 are t=0,t=-3,t=6
Find the zeros of 4t^3-12t^2-72t+25=25
The zeros of 4t^3-12t^2-72t+25=25 are t=0,t=-3,t=6