What is the answer to solvefor x,sqrt(xy)-4y^2=12 ?

The answer to solvefor x,sqrt(xy)-4y^2=12 is x=(144+96y^2+16y^4)/y

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solvefor x,sqrt(xy)-4y^2=12

solve for

x, x y - 4 y^{2} = 12

x = \frac{144 + 96 y ^{2} + 16 y ^{4}}{y}

Solution steps

x y - 4 y^{2} = 12

Move

4 y^{2}

to the right side

x y = 12 + 4 y^{2}

Square both sides:

x y = 144 + 96 y^{2} + 16 y^{4}

x y = 144 + 96 y^{2} + 16 y^{4}

Solve

x y = 144 + 96 y^{2} + 16 y^{4} : x = \frac{144 + 96 y ^{2} + 16 y ^{4}}{y}

x = \frac{144 + 96 y ^{2} + 16 y ^{4}}{y}

Verify Solutions:

x = \frac{144 + 96 y ^{2} + 16 y ^{4}}{y}

True

The solution is

x = \frac{144 + 96 y ^{2} + 16 y ^{4}}{y}

19 - 5 x = x - 5

1 - \frac{1}{3 t ^{\frac{2}{3}}} = 0

5 x + 34 = x + 8

16 - 4 x = 6

3 x^{\frac{2}{3}} - 2 x = 0

What is the answer to solvefor x,sqrt(xy)-4y^2=12 ?
The answer to solvefor x,sqrt(xy)-4y^2=12 is x=(144+96y^2+16y^4)/y