What is the answer to \sqrt[4]{27-2x}=\sqrt[4]{x-3} ?

The answer to \sqrt[4]{27-2x}=\sqrt[4]{x-3} is x=10

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\sqrt[4]{27-2x}=\sqrt[4]{x-3}

4 27 - 2 x = 4 x - 3

x = 10

Solution steps

4 27 - 2 x = 4 x - 3

Take both sides of the equation to the power of

4 : 27 - 2 x = x - 3

27 - 2 x = x - 3

Solve

27 - 2 x = x - 3 : x = 10

x = 10

Verify Solutions:

x = 10

True

The solution is

x = 10

x + 10 - 4 = x

x - 1 = x + 3 + 2

2 x - 1 + 3 = 6

2 x - 1 + 4 = 9

3 2 + x - 3 2 - x = 34

What is the answer to \sqrt[4]{27-2x}=\sqrt[4]{x-3} ?
The answer to \sqrt[4]{27-2x}=\sqrt[4]{x-3} is x=10
Solve for x: \sqrt[4]{27-2x}=\sqrt[4]{x-3}
The solution is x=10