What is the answer to (-2x^2+1)/(sqrt(1-x^2))=0 ?

The answer to (-2x^2+1)/(sqrt(1-x^2))=0 is x= 1/(sqrt(2)),x=-1/(sqrt(2))

Solve for x: (-2x^2+1)/(sqrt(1-x^2))=0

The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))

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\frac{- 2 x ^{2} + 1}{1 - x ^{2}} = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

\frac{- 2 x ^{2} + 1}{1 - x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x^{2} + 1 = 0

Solve

- 2 x^{2} + 1 = 0 : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{1}{2}

True

The solutions are

x = \frac{1}{2}, x = - \frac{1}{2}

x + 13 - x + 1 = 2

2 x + 80 + 17 = 25

5 x + 29 - 12 = - 5

7 x = x + 10

(x - 7)^{\frac{2}{3}} = 4

What is the answer to (-2x^2+1)/(sqrt(1-x^2))=0 ?
The answer to (-2x^2+1)/(sqrt(1-x^2))=0 is x= 1/(sqrt(2)),x=-1/(sqrt(2))
Solve for x: (-2x^2+1)/(sqrt(1-x^2))=0
The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))