What is the answer to 2\times \sqrt[3]{x+2}=-4 ?

The answer to 2\times \sqrt[3]{x+2}=-4 is x=-10

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2\times \sqrt[3]{x+2}=-4

2 \cdot 3 x + 2 = - 4

x = - 10

Solution steps

2 3 x + 2 = - 4

Divide both sides by

2

3 x + 2 = - 2

Take both sides of the equation to the power of

3 : x + 2 = - 8

x + 2 = - 8

Solve

x + 2 = - 8 : x = - 10

x = - 10

Verify Solutions:

x = - 10

True

The solution is

x = - 10

4 x - 40 = - 20

\frac{8 x - 32}{45 - 6 x} 2 x - 15 = 0

5 = a^{2} + 3^{2}

x^{2} - 5 x + 1 - 1 - 8 x = 0

6 + 3 y - 4 = 9

What is the answer to 2\times \sqrt[3]{x+2}=-4 ?
The answer to 2\times \sqrt[3]{x+2}=-4 is x=-10
Solve for x: 2\times \sqrt[3]{x+2}=-4
The solution is x=-10