What is the answer to log_{3}(x^2-2x)=1 ?

The answer to log_{3}(x^2-2x)=1 is x=3,x=-1

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log_{3}(x^2-2x)=1

lo g_{3} (x^{2} - 2 x) = 1

x = 3, x = - 1

Solution steps

lo g_{3} (x^{2} - 2 x) = 1

Apply log rules

x^{2} - 2 x = 3

Solve

x^{2} - 2 x = 3 : x = 3, x = - 1

x = 3, x = - 1

7 lo g_{e} (x) + 1 = 0

2 = lo g_{5} (t)

y, lo g_{8} (x) - 5 lo g_{8} (y) = \frac{5}{3}

lo g_{5} (x^{2} - 2 x + 5) = 1

lo g_{x - 5} (49) = 2

What is the answer to log_{3}(x^2-2x)=1 ?
The answer to log_{3}(x^2-2x)=1 is x=3,x=-1
Solve for x: log_{3}(x^2-2x)=1
The solution is x=3,x=-1