What is the answer to solvefor x,z=ln(x^2)+2xy-2y ?

The answer to solvefor x,z=ln(x^2)+2xy-2y is No Solution for x\in\mathbb{R}

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solvefor x,z=ln(x^2)+2xy-2y

solve for

x, z = ln (x^{2}) + 2 x y - 2 y

No Solution for x \in R

Solution steps

z = ln (x^{2}) + 2 x y - 2 y

Switch sides

ln (x^{2}) + 2 x y - 2 y = z

Move

2 x y

to the right side

ln (x^{2}) - 2 y = z - 2 x y

Move

2 y

to the right side

ln (x^{2}) = z - 2 x y + 2 y

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x^{2})} = e^{z - 2 x y + 2 y}

Simplify

e^{l n (x^{2})} : x^{2}

x^{2} = e^{z - 2 x y + 2 y}

Solve

x^{2} = e^{z - 2 x y + 2 y} :

No Solution for

x \in R

No Solution for x \in R

lo g_{10} (x + 7) = lo g_{10} (x) + lo g_{10} (7)

lo g_{10} (2 x + 50) = 2

lo g_{3} (x) = 0.25

lo g_{3} (5 - x) = 2

lo g_{4} (x + 8) - \frac{1}{2} = 0

What is the answer to solvefor x,z=ln(x^2)+2xy-2y ?
The answer to solvefor x,z=ln(x^2)+2xy-2y is No Solution for x\in\mathbb{R}