What is the answer to log_{10}(2x-3)=2 ?

The answer to log_{10}(2x-3)=2 is x= 103/2

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log_{10}(2x-3)=2

lo g_{10} (2 x - 3) = 2

x = \frac{103}{2}

Decimal

x = 51.5

Solution steps

lo g_{10} (2 x - 3) = 2

Apply log rules

2 x - 3 = 100

Solve

2 x - 3 = 100 : x = \frac{103}{2}

x = \frac{103}{2}

lo g_{x} (0.5) = - 1

lo g_{3} (x + 2) = - 4

lo g_{4} (x - 6) + 1 = 3 - lo g_{4} (x)

y, ln (x^{2} + y^{2} - 1) = 0

lo g_{x + 8} (2 x^{2} - 5 x - 8) = 2

What is the answer to log_{10}(2x-3)=2 ?
The answer to log_{10}(2x-3)=2 is x= 103/2
Solve for x: log_{10}(2x-3)=2
The solution is x= 103/2