What is the answer to log_{3}(x+2)=-4 ?

The answer to log_{3}(x+2)=-4 is x=-161/81

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log_{3}(x+2)=-4

lo g_{3} (x + 2) = - 4

x = - \frac{161}{81}

Decimal

x = - 1.98765 \dots

Solution steps

lo g_{3} (x + 2) = - 4

Apply log rules

x + 2 = \frac{1}{81}

Solve

x + 2 = \frac{1}{81} : x = - \frac{161}{81}

x = - \frac{161}{81}

lo g_{4} (x - 6) + 1 = 3 - lo g_{4} (x)

y, ln (x^{2} + y^{2} - 1) = 0

lo g_{x + 8} (2 x^{2} - 5 x - 8) = 2

lo g_{x} (x) = 1

lo g_{x} (32) = 4

What is the answer to log_{3}(x+2)=-4 ?
The answer to log_{3}(x+2)=-4 is x=-161/81
Solve for x: log_{3}(x+2)=-4
The solution is x=-161/81