What is the answer to log_{12}(2x-6)+3=3 ?

The answer to log_{12}(2x-6)+3=3 is x= 7/2

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log_{12}(2x-6)+3=3

lo g_{12} (2 x - 6) + 3 = 3

x = \frac{7}{2}

Decimal

x = 3.5

Solution steps

lo g_{12} (2 x - 6) + 3 = 3

Subtract

3

from both sides

lo g_{12} (2 x - 6) + 3 - 3 = 3 - 3

Simplify

lo g_{12} (2 x - 6) = 0

Apply log rules

2 x - 6 = 1

Solve

2 x - 6 = 1 : x = \frac{7}{2}

x = \frac{7}{2}

Verify Solutions:

x = \frac{7}{2}

True

The solution is

x = \frac{7}{2}

ln (x) = 9.353416701

lo g_{2} (\frac{( 2 x + 1 )}{( x - 1 )}) = 3

10 lo g_{10} (\frac{x}{2}) = 5

2 \times lo g_{4} (x) = - 4

lo g_{3} (2 x - 5) = - 3

What is the answer to log_{12}(2x-6)+3=3 ?
The answer to log_{12}(2x-6)+3=3 is x= 7/2
Solve for x: log_{12}(2x-6)+3=3
The solution is x= 7/2