What is the answer to 8x^7ln(x)+x^7=0 ?

The answer to 8x^7ln(x)+x^7=0 is x= 1/(\sqrt[8]{e)}

Solve for x: 8x^7ln(x)+x^7=0

The solution is x= 1/(\sqrt[8]{e)}

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8 x^{7} ln (x) + x^{7} = 0

x = \frac{1}{8 e}

Decimal

x = 0.88249 \dots

Solution steps

8 x^{7} ln (x) + x^{7} = 0

Move

x^{7}

to the right side

8 x^{7} ln (x) = - x^{7}

Move

x^{7}

to the left side

8 x^{7} ln (x) + x^{7} = 0

Factor

8 x^{7} ln (x) + x^{7} : x^{7} (8 ln (x) + 1)

x^{7} (8 ln (x) + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 8 ln (x) + 1 = 0

Solve

8 ln (x) + 1 = 0 : x = \frac{1}{8 e}

Verify Solutions:

x = 0

False

, x = \frac{1}{8 e}

True

The solution is

x = \frac{1}{8 e}

a, lo g_{a} (3) = 0.44

lo g_{7} (2 x + 25) = 2

x = ln (1 + n)

lo g_{10} (x - 1) = 2 lo g_{10} (3)

ln (x - 7) - ln (3) = 2

What is the answer to 8x^7ln(x)+x^7=0 ?
The answer to 8x^7ln(x)+x^7=0 is x= 1/(\sqrt[8]{e)}
Solve for x: 8x^7ln(x)+x^7=0
The solution is x= 1/(\sqrt[8]{e)}