What is the answer to log_{2}(x^2-2x-27)=3 ?

The answer to log_{2}(x^2-2x-27)=3 is x=7,x=-5

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log_{2}(x^2-2x-27)=3

lo g_{2} (x^{2} - 2 x - 27) = 3

x = 7, x = - 5

Solution steps

lo g_{2} (x^{2} - 2 x - 27) = 3

Apply log rules

x^{2} - 2 x - 27 = 8

Solve

x^{2} - 2 x - 27 = 8 : x = 7, x = - 5

x = 7, x = - 5

0 = 56 x^{6} ln (x) + 15 x^{6}

lo g_{\frac{1}{5}} (x + 7) = - 3

y, ln (x y) + 5 x = 30

a, ln (a) = ln (b)

x^{2 l o g_{10} (x)} = 100 x^{3}

What is the answer to log_{2}(x^2-2x-27)=3 ?
The answer to log_{2}(x^2-2x-27)=3 is x=7,x=-5
Solve for x: log_{2}(x^2-2x-27)=3
The solution is x=7,x=-5