What is the answer to |x^2-4x-8|=4 ?

The answer to |x^2-4x-8|=4 is x=-2\lor x=2(1-sqrt(2))\lor x=2(1+sqrt(2))\lor x=6

Solve for x: |x^2-4x-8|=4

The solution is x=-2\lor x=2(1-sqrt(2))\lor x=2(1+sqrt(2))\lor x=6

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x^{2} - 4 x - 8 = 4

x = - 2 or x = 2 (1 - 2) or x = 2 (1 + 2) or x = 6

Decimal

x = - 2, x = - 0.82842 \dots, x = 4.82842 \dots, x = 6

Solution steps

x^{2} - 4 x - 8 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 4 x - 8 = - 4 or x^{2} - 4 x - 8 = 4

x^{2} - 4 x - 8 = - 4 or x^{2} - 4 x - 8 = 4

(x = 2 (1 - 2) or x = 2 (1 + 2)) or (x = - 2 or x = 6)

x = - 2 or x = 2 (1 - 2) or x = 2 (1 + 2) or x = 6

∣ 3 x + 12 ∣ = 9 x

x^{2} + x - 4 = 2

∣ x + 1 ∣ + 2 = 7

5 = - ∣ x - 2 ∣ + 1

∣ x + 9 ∣ = 14

What is the answer to |x^2-4x-8|=4 ?
The answer to |x^2-4x-8|=4 is x=-2\lor x=2(1-sqrt(2))\lor x=2(1+sqrt(2))\lor x=6
Solve for x: |x^2-4x-8|=4
The solution is x=-2\lor x=2(1-sqrt(2))\lor x=2(1+sqrt(2))\lor x=6