What are the solutions to the equation roots f(x)=(x-6)(2x+10) ?

The solutions to the equation roots f(x)=(x-6)(2x+10) are x=6,x=-5

Find the zeros of roots f(x)=(x-6)(2x+10)

The zeros of roots f(x)=(x-6)(2x+10) are x=6,x=-5

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roots

f (x) = (x - 6) (2 x + 10)

x = 6, x = - 5

Solution steps

(x - 6) (2 x + 10)

The roots are the intercepts with the x-axis

(y = 0)

(x - 6) (2 x + 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or 2 x + 10 = 0

Solve

x - 6 = 0 : x = 6

Solve

2 x + 10 = 0 : x = - 5

The solutions to the quadratic equation are:

x = 6, x = - 5

cot (θ)

Q u a d r a t i c (- 2.4)

g (x) = 5 x - 12 x^{2} + 3

∣ x ∣ > 11

125 0^{\frac{3}{4}}

What are the solutions to the equation roots f(x)=(x-6)(2x+10) ?
The solutions to the equation roots f(x)=(x-6)(2x+10) are x=6,x=-5
Find the zeros of roots f(x)=(x-6)(2x+10)
The zeros of roots f(x)=(x-6)(2x+10) are x=6,x=-5