What is the solution for y^{''}+9y=19 ?

The solution for y^{''}+9y=19 is y=c_{1}cos(3t)+c_{2}sin(3t)+19/9

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y^{''}+9y=19

y^{^{''}} + 9 y = 19

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{19}{9}

Solution steps

y^{''} (t) + 9 y = 19

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{19}{9}

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{19}{9}

f (x) = \frac{x ^{2}}{8 - 8 x}

(\frac{1}{y ^{2}} - \frac{5}{y ^{4}}) (y + 9 y^{3})

\frac{d y}{d x} = \frac{1}{10} y (500 - y)

x \to \infty lim (7 x^{2} + 6)

y^{^{'}} = tan (x + y)

What is the solution for y^{''}+9y=19 ?
The solution for y^{''}+9y=19 is y=c_{1}cos(3t)+c_{2}sin(3t)+19/9