What is the derivative of f(x)=(4x^2-8x+8)e^x ?

The derivative of f(x)=(4x^2-8x+8)e^x is 4e^xx^2

What is the first derivative of f(x)=(4x^2-8x+8)e^x ?

The first derivative of f(x)=(4x^2-8x+8)e^x is 4e^xx^2

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derivative of

f (x) = (4 x^{2} - 8 x + 8) e^{x}

4 e^{x} x^{2}

Solution steps

\frac{d}{d x} ((4 x^{2} - 8 x + 8) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 4 x^{2} - 8 x + 8, g = e^{x}

= \frac{d}{d x} (4 x^{2} - 8 x + 8) e^{x} + \frac{d}{d x} (e^{x}) (4 x^{2} - 8 x + 8)

\frac{d}{d x} (4 x^{2} - 8 x + 8) = 8 x - 8

\frac{d}{d x} (e^{x}) = e^{x}

= (8 x - 8) e^{x} + e^{x} (4 x^{2} - 8 x + 8)

Simplify

(8 x - 8) e^{x} + e^{x} (4 x^{2} - 8 x + 8) : 4 e^{x} x^{2}

= 4 e^{x} x^{2}

\frac{\partial}{\partial y} (x e^{2 y} sin (7 z))

24 x - 0.01 x^{2}

y^{^{''}} + 121 y = sec (11 x)

x \to 0 - lim (\frac{1 - e ^{- 3 x}}{x})

What is the derivative of f(x)=(4x^2-8x+8)e^x ?
The derivative of f(x)=(4x^2-8x+8)e^x is 4e^xx^2
What is the first derivative of f(x)=(4x^2-8x+8)e^x ?
The first derivative of f(x)=(4x^2-8x+8)e^x is 4e^xx^2