What is (\partial)/(\partial v)(uv^2+w^3) ?

The answer to (\partial)/(\partial v)(uv^2+w^3) is 2uv

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(\partial)/(\partial v)(uv^2+w^3)

\frac{\partial}{\partial v} (u v^{2} + w^{3})

2 uv

Solution steps

\frac{\partial}{\partial v} (u v^{2} + w^{3})

Treat

u, w

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial v} (u v^{2}) + \frac{\partial}{\partial v} (w^{3})

\frac{\partial}{\partial v} (u v^{2}) = 2 uv

\frac{\partial}{\partial v} (w^{3}) = 0

= 2 uv + 0

Simplify

= 2 uv

\int e^{5 x + 6} d x

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{2 t}

f (x) = x - 2 sin (x), at x = 0

x y^{^{''}} - y^{^{'}} = x^{2}

\frac{x - 5}{x ^{2} + 1}

What is (\partial)/(\partial v)(uv^2+w^3) ?
The answer to (\partial)/(\partial v)(uv^2+w^3) is 2uv