en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6y^'+7y=5

Solution

6 y^{^{'}} + 7 y = 5

Solution

y = - \frac{e ^{\frac{- 7 t - c _{1}}{6}}}{7} + \frac{5}{7}

Solution steps

6 y^{'} (t) + 7 y = 5

Solve separable ODE:

y = - \frac{e ^{\frac{- 7 t - c _{1}}{6}}}{7} + \frac{5}{7}

y = - \frac{e ^{\frac{- 7 t - c _{1}}{6}}}{7} + \frac{5}{7}

Popular Examples

(d^2)/(dx^2)(sin(x)-cos(x))

\frac{d ^{2}}{d x ^{2}} (sin (x) - cos (x))

6(x^2+y^2)dx+5xydy=0

6 (x^{2} + y^{2}) d x + 5 x y d y = 0

d/(d{y)}(({y})/({x)+{y}+{z}})

\frac{d}{d y} (\frac{y}{x + y + z})

derivative of sqrt(7)x-sqrt(2x)derivative of

7 x - 2 x

tangent of y=x^2+9,(4,25)tangent of

y = x^{2} + 9, (4, 25)

Frequently Asked Questions (FAQ)

What is the solution for 6y^'+7y=5 ?
The solution for 6y^'+7y=5 is y=-(e^{(-7t-c_{1})/6})/(7)+5/7