What is the tangent of y=x^2+9,(4,25) ?

The tangent of y=x^2+9,(4,25) is y=8x-7

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tangent of y=x^2+9,(4,25)

tangent of

y = x^{2} + 9, (4, 25)

y = 8 x - 7

Solution steps

Find the slope of

y = x^{2} + 9 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} + 9

(4, 25) : m = 8

Find the line with slope m=

8

and passing through

(4, 25) : y = 8 x - 7

y = 8 x - 7

\frac{d}{d x} (arctan (x^{3} - x))

cos (t) + t sin (t), at t = π

y = x, y = \frac{1}{4} x + 1, x = 0

\int x y cos (x y) d x

\frac{d y}{d x} = (y - y^{2})