What is area y=sqrt(x),y= 1/4 x+1,x=0 ?

The answer to area y=sqrt(x),y= 1/4 x+1,x=0 is 2/3

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area y=sqrt(x),y= 1/4 x+1,x=0

area

y = x, y = \frac{1}{4} x + 1, x = 0

\frac{2}{3}

Solution steps

Apply the area formula:

\int_{0}^{4} x - (\frac{1}{4} x + 1) d x

Solve

\int_{0}^{4} x - (\frac{1}{4} x + 1) d x : \frac{2}{3}

The area is:

= \frac{2}{3}

\int x y cos (x y) d x

\frac{d y}{d x} = (y - y^{2})

\int e^{\frac{2}{t}} d t

\int sin^{3} (5 x) cos (5 x) d x

\int_{1}^{2} x 3^{(x^{2})} d x

What is area y=sqrt(x),y= 1/4 x+1,x=0 ?
The answer to area y=sqrt(x),y= 1/4 x+1,x=0 is 2/3