What is the integral of tan(x)sec^2(x) ?

The integral of tan(x)sec^2(x) is (tan^2(x))/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of tan(x)sec^2(x)

\int tan (x) sec^{2} (x) d x

\frac{tan ^{2} ( x )}{2} + C

Solution steps

\int tan (x) sec^{2} (x) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = tan (x)

= \frac{tan ^{2} ( x )}{2}

Add a constant to the solution

= \frac{tan ^{2} ( x )}{2} + C

\int \frac{1}{2} sin (\frac{2 π t}{5}) d t

\int (1 + x)^{- 2} d x

\int \frac{8}{t ^{2} ( t ^{2} - 4 )} d t

x \to 2 lim (5 x^{2} - 4 x + 3)

y = 9 x - 4 x^{2}, (- 2, - 34)

What is the integral of tan(x)sec^2(x) ?
The integral of tan(x)sec^2(x) is (tan^2(x))/2+C