What is the d/(d{x)}({x}-2{y}+2{z}) ?

The d/(d{x)}({x}-2{y}+2{z}) is 1

What is the first d/(d{x)}({x}-2{y}+2{z}) ?

The first d/(d{x)}({x}-2{y}+2{z}) is 1

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\frac{d}{d x} (x - 2 y + 2 z)

1

Solution steps

\frac{d}{d x} (x - 2 y + 2 z)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) - \frac{d}{d x} (2 y) + \frac{d}{d x} (2 z)

\frac{d}{d x} (x) = 1

\frac{d}{d x} (2 y) = 0

\frac{d}{d x} (2 z) = 0

= 1 - 0 + 0

Simplify

= 1

\int \frac{3}{1 + x ^{2}} d x

\frac{1}{( s - 1 ) ^{2} + 1}

f (x) = csc (x), at x = \frac{π}{6}

\frac{d}{d x} (y^{3} + x y^{2} + y)

\frac{( x + 1 ) ( x ^{2} + 1 )}{x - 2}

What is the d/(d{x)}({x}-2{y}+2{z}) ?
The d/(d{x)}({x}-2{y}+2{z}) is 1
What is the first d/(d{x)}({x}-2{y}+2{z}) ?
The first d/(d{x)}({x}-2{y}+2{z}) is 1