What is the derivative of 3x^2+12x+9 ?

The derivative of 3x^2+12x+9 is 6x+12

What is the first derivative of 3x^2+12x+9 ?

The first derivative of 3x^2+12x+9 is 6x+12

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\frac{d}{d x} (3 x^{2} + 12 x + 9)

6 x + 12

Solution steps

\frac{d}{d x} (3 x^{2} + 12 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (12 x) + \frac{d}{d x} (9)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (9) = 0

= 6 x + 12 + 0

Simplify

= 6 x + 12

\int \frac{1}{36 e ^{- 5 x} + e ^{5 x}} d x

(4) (8.8)

\int 9 (9 x + 2) d x

sin (2 x), 0.0001

x \to 3 lim ([\frac{8}{8 + 10}])

What is the derivative of 3x^2+12x+9 ?
The derivative of 3x^2+12x+9 is 6x+12
What is the first derivative of 3x^2+12x+9 ?
The first derivative of 3x^2+12x+9 is 6x+12