What is the integral of 9(9x+2) ?

The integral of 9(9x+2) is 9((9x^2)/2+2x)+C

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integral of 9(9x+2)

\int 9 (9 x + 2) d x

9 (\frac{9 x ^{2}}{2} + 2 x) + C

Solution steps

\int 9 (9 x + 2) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int 9 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 9 (\int 9 x d x + \int 2 d x)

\int 9 x d x = \frac{9 x ^{2}}{2}

\int 2 d x = 2 x

= 9 (\frac{9 x ^{2}}{2} + 2 x)

Add a constant to the solution

= 9 (\frac{9 x ^{2}}{2} + 2 x) + C

sin (2 x), 0.0001

x \to 3 lim ([\frac{8}{8 + 10}])

\frac{\partial}{\partial y} (tan (\frac{y}{x}))

f (x) = sin (7 x)

\frac{1}{3} \cdot t^{3} - 9 \cdot t + 2