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Popular >

derivative of f(x)=sqrt(2x^2-x)

Solution

derivative of

f (x) = 2 x^{2} - x

Solution

\frac{4 x - 1}{2 2 x ^{2} - x}

Solution steps

\frac{d}{d x} (2 x^{2} - x)

Apply the chain rule:

\frac{1}{2 2 x ^{2} - x} \frac{d}{d x} (2 x^{2} - x)

= \frac{1}{2 2 x ^{2} - x} \frac{d}{d x} (2 x^{2} - x)

\frac{d}{d x} (2 x^{2} - x) = 4 x - 1

= \frac{1}{2 2 x ^{2} - x} (4 x - 1)

Simplify

\frac{1}{2 2 x ^{2} - x} (4 x - 1) : \frac{4 x - 1}{2 2 x ^{2} - x}

= \frac{4 x - 1}{2 2 x ^{2} - x}

Popular Examples

integral of 1/(sqrt(t^2-2t+26))

\int \frac{1}{t ^{2} - 2 t + 26} d t

y^{^{'}} + y^{2} = 0

integral from 1/2 to 5 of 12xln(2x)

\int_{\frac{1}{2}}^{5} 12 x ln (2 x) d x

slope of 3/x slope

\frac{3}{x}

limit as x approaches 1 of 1/x+1

x \to 1 lim (\frac{1}{x} + 1)

Frequently Asked Questions (FAQ)

What is the derivative of f(x)=sqrt(2x^2-x) ?
The derivative of f(x)=sqrt(2x^2-x) is (4x-1)/(2sqrt(2x^2-x))
What is the first derivative of f(x)=sqrt(2x^2-x) ?
The first derivative of f(x)=sqrt(2x^2-x) is (4x-1)/(2sqrt(2x^2-x))