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Popular >

y^'+y^2=0

Solution

y^{^{'}} + y^{2} = 0

Solution

y = - \frac{1}{- t + c _{1}}

Solution steps

y^{'} (t) + y^{2} = 0

Solve separable ODE:

y = - \frac{1}{- t + c _{1}}

y = - \frac{1}{- t + c _{1}}

Popular Examples

integral from 1/2 to 5 of 12xln(2x)

\int_{\frac{1}{2}}^{5} 12 x ln (2 x) d x

slope of 3/x slope

\frac{3}{x}

limit as x approaches 1 of 1/x+1

x \to 1 lim (\frac{1}{x} + 1)

y^{''}+9y=26e^{2x}

y^{^{''}} + 9 y = 26 e^{2 x}

integral from 0 to 5 of pi(2sqrt(3y))^2

\int_{0}^{5} π (2 3 y)^{2} d y

Frequently Asked Questions (FAQ)

What is the solution for y^'+y^2=0 ?
The solution for y^'+y^2=0 is y=-1/(-t+c_{1)}