What is the slope ofintercept (-1,1),(5,-1) ?

The slope ofintercept (-1,1),(5,-1) is y=-1/3 x+2/3

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slope ofintercept (-1,1),(5,-1)

slope intercept

(- 1, 1), (5, - 1)

y = - \frac{1}{3} x + \frac{2}{3}

Solution steps

Compute the slope

(- 1, 1), (5, - 1) : m = - \frac{1}{3}

Compute the

y

intercept:

b = \frac{2}{3}

Construct the line equation

y = mx + b

where

m = - \frac{1}{3}

and

b = \frac{2}{3}

y = - \frac{1}{3} x + \frac{2}{3}

\frac{d}{d x} (e^{g (x)})

\frac{d ^{2}}{d x ^{2}} (sin (x))

x \to 0 lim (\frac{6 x}{x ^{4}})

x \to π + lim (\frac{π}{sin ( π )})

\int - cos (x) + C x + C d x

What is the slope ofintercept (-1,1),(5,-1) ?
The slope ofintercept (-1,1),(5,-1) is y=-1/3 x+2/3