What is (2x)dx+(2-3x^2y^{-1})dy=0 ?

The solution to (2x)dx+(2-3x^2y^{-1})dy=0 is Parabola with (h,k)=(0,0),p= 1/(4d)

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(2x)dx+(2-3x^2y^{-1})dy=0

(2 x) d x + (2 - 3 x^{2} y^{- 1}) d y = 0

(h, k) = (0, 0), p = \frac{1}{4 d}

Solution steps

2 x d x + (2 - 3 x^{2} y^{- 1}) d y = 0

Rewrite

2 x d x + (2 - 3 x^{2} y^{- 1}) d y = 0

in the standard form

4 \cdot \frac{1}{4 d} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4 d}

\int 4 e^{x} (e^{x} - 1) d x

\frac{2 x ^{9} - 5 x + x}{x ^{4}}

x \to 1 + lim (\frac{1}{x - 1})

(e^{2 x} + 4) (\frac{d y}{d x}) = y

\frac{d}{d x} (2 x - ln (x))

What is (2x)dx+(2-3x^2y^{-1})dy=0 ?
The solution to (2x)dx+(2-3x^2y^{-1})dy=0 is Parabola with (h,k)=(0,0),p= 1/(4d)