What is the derivative of 2x-ln(x) ?

The derivative of 2x-ln(x) is 2-1/x

What is the first derivative of 2x-ln(x) ?

The first derivative of 2x-ln(x) is 2-1/x

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\frac{d}{d x} (2 x - ln (x))

2 - \frac{1}{x}

Solution steps

\frac{d}{d x} (2 x - ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (ln (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 - \frac{1}{x}

y^{^{'}} = - k y

arctan (\frac{x}{5})

\int_{- 1}^{0} \frac{1}{x ^{3}} d x

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{6}{x ^{4}}) (x + 8 x^{3}))

What is the derivative of 2x-ln(x) ?
The derivative of 2x-ln(x) is 2-1/x
What is the first derivative of 2x-ln(x) ?
The first derivative of 2x-ln(x) is 2-1/x