What is the derivative of f(x)=sqrt(x)+7 ?

The derivative of f(x)=sqrt(x)+7 is 1/(2sqrt(x))

What is the first derivative of f(x)=sqrt(x)+7 ?

The first derivative of f(x)=sqrt(x)+7 is 1/(2sqrt(x))

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derivative of

f (x) = x + 7

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (7)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (7) = 0

= \frac{1}{2 x} + 0

Simplify

= \frac{1}{2 x}

x \to - 3 - lim (\frac{x + 2}{x + 3})

\int 2 x - x^{2} d x

y = 50 - x^{2}

f (x) = 3 cos (x)

x \to - 5 + lim (\frac{1}{x ^{2} - 25})

What is the derivative of f(x)=sqrt(x)+7 ?
The derivative of f(x)=sqrt(x)+7 is 1/(2sqrt(x))
What is the first derivative of f(x)=sqrt(x)+7 ?
The first derivative of f(x)=sqrt(x)+7 is 1/(2sqrt(x))