What is the solution for ((dy)/(dx))=((2x(y-1)))/(x^2+3) ?

The solution for ((dy)/(dx))=((2x(y-1)))/(x^2+3) is y=e^{c_{1}}x^2+3e^{c_{1}}+1

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((dy)/(dx))=((2x(y-1)))/(x^2+3)

(\frac{d y}{d x}) = \frac{( 2 x ( y - 1 ) )}{x ^{2} + 3}

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

Solution steps

(\frac{d y}{d x}) = \frac{( 2 x ( y - 1 ) )}{x ^{2} + 3}

Solve separable ODE:

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

y^{2} + 1 d x = x y d y

\frac{d}{d x} (\frac{x}{x ^{2} + t ^{2}})

\int_{0}^{3} - x^{2} d x

\int tan (3 x) sec^{\frac{5}{4}} (3 x) d x

y = x, (36, 6)

What is the solution for ((dy)/(dx))=((2x(y-1)))/(x^2+3) ?
The solution for ((dy)/(dx))=((2x(y-1)))/(x^2+3) is y=e^{c_{1}}x^2+3e^{c_{1}}+1