What is (\partial)/(\partial x)(e^{(t-x)}) ?

The answer to (\partial)/(\partial x)(e^{(t-x)}) is -e^{t-x}

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(\partial)/(\partial x)(e^{(t-x)})

\frac{\partial}{\partial x} (e^{(t - x)})

- e^{t - x}

Solution steps

\frac{\partial}{\partial x} (e^{(t - x)})

Treat

t

as a constant

Apply the chain rule:

e^{t - x} \frac{\partial}{\partial x} (t - x)

= e^{t - x} \frac{\partial}{\partial x} (t - x)

\frac{\partial}{\partial x} (t - x) = - 1

= e^{t - x} (- 1)

Simplify

= - e^{t - x}

\frac{d}{d x} (4 x^{2} - 5)

y = 3 x^{3} - 10 x - \frac{4}{x ^{3}}

\frac{\partial}{\partial x} (\frac{3 x y}{x ^{4} + y ^{4}})

\frac{\partial}{\partial x} (x + 2 y + 1)

h \to 0 lim (\frac{( 2 + h ) ^{2} - 8}{h})

What is (\partial)/(\partial x)(e^{(t-x)}) ?
The answer to (\partial)/(\partial x)(e^{(t-x)}) is -e^{t-x}