What is implicit (dy)/(dx),x^2-y^2=64 ?

The answer to implicit (dy)/(dx),x^2-y^2=64 is (dy)/(dx)= x/y

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implicit (dy)/(dx),x^2-y^2=64

implicit derivative

\frac{d y}{d x}, x^{2} - y^{2} = 64

\frac{d y}{d x} = \frac{x}{y}

Solution steps

x^{2} - y^{2} = 64

Treat

y

y (x)

Differentiate both sides:

2 x - 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{x}{y}

\frac{d y}{d x} = \frac{x}{y}

\frac{d}{d x} (sec (\frac{π}{4}))

cos (\frac{x + 1}{x - 1})

F (x) = \frac{3}{1 + x ^{2}}

\int 3 x - 5 d x

\frac{\partial}{\partial z} (x^{2} y)

What is implicit (dy)/(dx),x^2-y^2=64 ?
The answer to implicit (dy)/(dx),x^2-y^2=64 is (dy)/(dx)= x/y