What is area f(x)=sin(2x),-pi/2 , pi/6 ?

The answer to area f(x)=sin(2x),-pi/2 , pi/6 is 5/4

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area f(x)=sin(2x),-pi/2 , pi/6

area

f (x) = sin (2 x), - \frac{π}{2}, \frac{π}{6}

\frac{5}{4}

Solution steps

Apply the area formula:

\int_{- \frac{π}{2}}^{\frac{π}{6}} ∣ sin (2 x) ∣ d x

Solve

\int_{- \frac{π}{2}}^{\frac{π}{6}} ∣ sin (2 x) ∣ d x : \frac{5}{4}

The area is:

= \frac{5}{4}

\frac{d ^{2}}{d x ^{2}} (11 e^{x^{2}})

(- 1 x - 2)^{10}

- 204 x

\frac{d}{d x} (x^{2} - 2 x + 1)

\int \frac{ln ( 11 x )}{x} d x

What is area f(x)=sin(2x),-pi/2 , pi/6 ?
The answer to area f(x)=sin(2x),-pi/2 , pi/6 is 5/4