What is laplacetransform-3sin(5t) ?

The answer to laplacetransform-3sin(5t) is -(15)/(s^2+25)

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laplacetransform-3sin(5t)

laplace transform

- 3 sin (5 t)

- \frac{15}{s ^{2} + 25}

Solution steps

L {- 3 sin (5 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 3 L {sin (5 t)}

L {sin (5 t)} : \frac{5}{s ^{2} + 25}

= - 3 \cdot \frac{5}{s ^{2} + 25}

Refine

- 3 \frac{5}{s ^{2} + 25} : - \frac{15}{s ^{2} + 25}

= - \frac{15}{s ^{2} + 25}

\frac{d x}{d y} = - \frac{1}{7} x

\int \frac{2 x + 1}{( x - 2 ) ( x - 3 ) ^{2}} d x

\frac{d}{d x} (x^{5} - 3 x^{3} + x - 1)

\int \frac{1}{x ( x ^{4} + 1 )} d x

y = (3 x^{3} + 2 x)^{\frac{1}{2}}

What is laplacetransform-3sin(5t) ?
The answer to laplacetransform-3sin(5t) is -(15)/(s^2+25)