What is the derivative of x^5-3x^3+x-1 ?

The derivative of x^5-3x^3+x-1 is 5x^4-9x^2+1

What is the first derivative of x^5-3x^3+x-1 ?

The first derivative of x^5-3x^3+x-1 is 5x^4-9x^2+1

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\frac{d}{d x} (x^{5} - 3 x^{3} + x - 1)

5 x^{4} - 9 x^{2} + 1

Solution steps

\frac{d}{d x} (x^{5} - 3 x^{3} + x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{5}) - \frac{d}{d x} (3 x^{3}) + \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 5 x^{4} - 9 x^{2} + 1 - 0

Simplify

= 5 x^{4} - 9 x^{2} + 1

\int \frac{1}{x ( x ^{4} + 1 )} d x

y = (3 x^{3} + 2 x)^{\frac{1}{2}}

f (x) = e^{- 9}

\int_{0}^{0.08} 2000 x d x

\frac{d}{d x} (\frac{2 x}{x + 2})

What is the derivative of x^5-3x^3+x-1 ?
The derivative of x^5-3x^3+x-1 is 5x^4-9x^2+1
What is the first derivative of x^5-3x^3+x-1 ?
The first derivative of x^5-3x^3+x-1 is 5x^4-9x^2+1