What is the derivative of (2x/(x+2)) ?

The derivative of (2x/(x+2)) is 4/((x+2)^2)

What is the first derivative of (2x/(x+2)) ?

The first derivative of (2x/(x+2)) is 4/((x+2)^2)

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\frac{d}{d x} (\frac{2 x}{x + 2})

\frac{4}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x}{x + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{x + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} ( x + 2 ) - \frac{d}{d x} ( x + 2 ) x}{( x + 2 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 2) = 1

= 2 \cdot \frac{1 \cdot ( x + 2 ) - 1 \cdot x}{( x + 2 ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot ( x + 2 ) - 1 \cdot x}{( x + 2 ) ^{2}} : \frac{4}{( x + 2 ) ^{2}}

= \frac{4}{( x + 2 ) ^{2}}

\int 2 + 2 sin (x) d x

y = 4 x sin (x), (\frac{π}{2}, 2 π)

(x y + 2 y) d x + (3 x) d y = 0

x^{2} + 3 x

\frac{d ^{2} y}{d t ^{2}} - 2 \frac{d y}{d t} - 8 y = 0

What is the derivative of (2x/(x+2)) ?
The derivative of (2x/(x+2)) is 4/((x+2)^2)
What is the first derivative of (2x/(x+2)) ?
The first derivative of (2x/(x+2)) is 4/((x+2)^2)