What is (\partial)/(\partial v)(u+v^2) ?

The answer to (\partial)/(\partial v)(u+v^2) is 2v

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(\partial)/(\partial v)(u+v^2)

\frac{\partial}{\partial v} (u + v^{2})

2 v

Solution steps

\frac{\partial}{\partial v} (u + v^{2})

Treat

u

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial v} (u) + \frac{\partial}{\partial v} (v^{2})

\frac{\partial}{\partial v} (u) = 0

\frac{\partial}{\partial v} (v^{2}) = 2 v

= 0 + 2 v

Simplify

= 2 v

\frac{d y}{d x} + y = - e^{x}

x \to \frac{π}{2} lim (ln (cos (x)))

\int t^{2} \cdot cos (t) d t

\frac{d}{d x} (x^{3} (x - 7)^{2})

y = x^{2} - 4 x + 3, y = 3 + 4 x - x^{2}

What is (\partial)/(\partial v)(u+v^2) ?
The answer to (\partial)/(\partial v)(u+v^2) is 2v